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Let’s check out your problem:
Expand. If necessary, combine like terms.
\newline
(
7
x
−
1
)
2
=
(7x-1)^2=
(
7
x
−
1
)
2
=
View step-by-step help
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Math Problems
Algebra 1
Multiply two binomials: special cases
Full solution
Q.
Expand. If necessary, combine like terms.
\newline
(
7
x
−
1
)
2
=
(7x-1)^2=
(
7
x
−
1
)
2
=
Identify special case:
Identify the special case that applies to this problem.
\newline
(
7
x
−
1
)
2
(7x - 1)^2
(
7
x
−
1
)
2
is in the form of
(
a
−
b
)
2
(a - b)^2
(
a
−
b
)
2
.
\newline
Special case:
(
a
−
b
)
2
=
a
2
−
2
a
b
+
b
2
(a - b)^2 = a^2 - 2ab + b^2
(
a
−
b
)
2
=
a
2
−
2
ab
+
b
2
Identify values of a and b:
Identify the values of
a
a
a
and
b
b
b
. Compare
(
7
x
−
1
)
2
(7x - 1)^2
(
7
x
−
1
)
2
with
(
a
−
b
)
2
(a - b)^2
(
a
−
b
)
2
.
a
=
7
x
a = 7x
a
=
7
x
b
=
1
b = 1
b
=
1
Apply binomial formula:
Apply the square of a binomial formula to expand
(
7
x
−
1
)
2
(7x - 1)^2
(
7
x
−
1
)
2
.
\newline
(
a
−
b
)
2
=
a
2
−
2
a
b
+
b
2
(a - b)^2 = a^2 - 2ab + b^2
(
a
−
b
)
2
=
a
2
−
2
ab
+
b
2
\newline
(
7
x
−
1
)
2
=
(
7
x
)
2
−
2
(
7
x
)
(
1
)
+
1
2
(7x - 1)^2 = (7x)^2 - 2(7x)(1) + 1^2
(
7
x
−
1
)
2
=
(
7
x
)
2
−
2
(
7
x
)
(
1
)
+
1
2
Simplify the expression:
Simplify
(
7
x
)
2
−
2
(
7
x
)
(
1
)
+
1
2
(7x)^2 - 2(7x)(1) + 1^2
(
7
x
)
2
−
2
(
7
x
)
(
1
)
+
1
2
.
\newline
(
7
x
)
2
−
2
(
7
x
)
(
1
)
+
1
2
(7x)^2 - 2(7x)(1) + 1^2
(
7
x
)
2
−
2
(
7
x
)
(
1
)
+
1
2
\newline
=
(
7
x
⋅
7
x
)
−
(
2
⋅
7
⋅
1
)
x
+
1
⋅
1
(7x \cdot 7x) - (2 \cdot 7 \cdot 1)x + 1 \cdot 1
(
7
x
⋅
7
x
)
−
(
2
⋅
7
⋅
1
)
x
+
1
⋅
1
\newline
=
49
x
2
−
14
x
+
1
49x^2 - 14x + 1
49
x
2
−
14
x
+
1
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\newline
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\newline
(
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(
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\newline
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\newline
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