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Let’s check out your problem:
Expand. If necessary, combine like terms.
\newline
(
7
+
x
)
(
7
−
x
)
=
(7+x)(7-x)=
(
7
+
x
)
(
7
−
x
)
=
View step-by-step help
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Math Problems
Algebra 1
Multiply two binomials: special cases
Full solution
Q.
Expand. If necessary, combine like terms.
\newline
(
7
+
x
)
(
7
−
x
)
=
(7+x)(7-x)=
(
7
+
x
)
(
7
−
x
)
=
Identify special case:
Identify the special case that applies here.
\newline
(
7
+
x
)
(
7
−
x
)
(7+x)(7-x)
(
7
+
x
)
(
7
−
x
)
is in the form of
(
a
+
b
)
(
a
−
b
)
(a + b)(a - b)
(
a
+
b
)
(
a
−
b
)
.
\newline
Special case:
(
a
+
b
)
(
a
−
b
)
=
a
2
−
b
2
(a + b)(a - b) = a^2 - b^2
(
a
+
b
)
(
a
−
b
)
=
a
2
−
b
2
Identify values of a and b:
Identify the values of
a
a
a
and
b
b
b
. Compare
(
7
+
x
)
(
7
−
x
)
(7+x)(7-x)
(
7
+
x
)
(
7
−
x
)
with
(
a
+
b
)
(
a
−
b
)
(a + b)(a - b)
(
a
+
b
)
(
a
−
b
)
.
a
=
7
a = 7
a
=
7
b
=
x
b = x
b
=
x
Apply difference of squares:
Apply the difference of squares to expand
(
7
+
x
)
(
7
−
x
)
(7+x)(7-x)
(
7
+
x
)
(
7
−
x
)
.
\newline
(
a
+
b
)
(
a
−
b
)
=
a
2
−
b
2
(a + b)(a - b) = a^2 - b^2
(
a
+
b
)
(
a
−
b
)
=
a
2
−
b
2
\newline
(
7
+
x
)
(
7
−
x
)
=
7
2
−
x
2
(7+x)(7-x) = 7^2 - x^2
(
7
+
x
)
(
7
−
x
)
=
7
2
−
x
2
Simplify expression:
Simplify
7
2
−
x
2
7^2 - x^2
7
2
−
x
2
.
\newline
7
2
−
x
2
=
49
−
x
2
7^2 - x^2 = 49 - x^2
7
2
−
x
2
=
49
−
x
2
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\newline
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\text{[[even][odd][neither]]}
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\newline
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\newline
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(
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\newline
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\newline
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