Expand. If necessary, combine like terms. (5x+1)(5x-1)=

Identify special case: Identify the special case that applies to the given expression. The expression (5x+1)(5x-1) is in the form of (a+b)(a-b). Special case: (a+b)(a-b) = a^2 - b^2Identify values of a and b: Identify the values of a and b. Compare (5x+1)(5x-1) with (a+b)(a-b). a = 5x b = 1Apply difference of squares formula: Apply the difference of squares formula to expand (5x+1)(5x-1). (a+b)(a-b) = a^2 - b^2 (5x+1)(5x-1) = (5x)^2 - (1)^2Simplify expression: Simplify (5x)^2 - (1)^2. (5x)^2 - (1)^2 = (5x * 5x) - (1 * 1) = 25x^2 - 1

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Expand. If necessary, combine like terms.

(5x+1)(5x-1)=

Expand. If necessary, combine like terms. $\newline$ $(5x+1)(5x-1)=$

View step-by-step help

Home

Math Problems

Algebra 1

Multiply two binomials: special cases

Full solution

Q. Expand. If necessary, combine like terms.

\newline

(5x+1)(5x-1)=

Identify special case: Identify the special case that applies to the given expression. $\newline$ The expression $(5x+1)(5x-1)$ is in the form of $(a+b)(a-b)$ . $\newline$ Special case: $(a+b)(a-b) = a^2 - b^2$
Identify values of a and b: Identify the values of a and b. $\newline$ Compare $(5x+1)(5x-1)$ with $(a+b)(a-b)$ . $\newline$ $a = 5x$ $\newline$ $b = 1$
Apply difference of squares formula: Apply the difference of squares formula to expand $(5x+1)(5x-1)$ . $\newline$ $(a+b)(a-b) = a^2 - b^2$ $\newline$ $(5x+1)(5x-1) = (5x)^2 - (1)^2$
Simplify expression: Simplify $(5x)^2 - (1)^2$ .
$(5x)^2 - (1)^2 = (5x \cdot 5x) - (1 \cdot 1)$
= $25x^2 - 1$