Expand. If necessary, combine like terms. (2x-3)(2x-3)=

Recognize the pattern: Recognize the pattern. The expression (2x-3)(2x-3) is in the form of (a-b)(a-b), which is a special case of the binomial product. Special case: (a-b)(a-b) = a^2 - 2ab + b^2Identify the values of a and b: Identify the values of a and b. Compare (2x-3)(2x-3) with (a-b)(a-b). a = 2x b = 3Apply the binomial product formula: Apply the binomial product formula. Using the formula (a-b)(a-b) = a^2 - 2ab + b^2, we expand (2x-3)(2x-3). (2x-3)(2x-3) = (2x)^2 - 2(2x)(3) + (3)^2Perform the calculations: Perform the calculations. (2x)^2 - 2(2x)(3) + (3)^2 = 4x^2 - 2(6x) + 9 = 4x^2 - 12x + 9

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Expand. If necessary, combine like terms.

(2x-3)(2x-3)=

Expand. If necessary, combine like terms. $\newline$ $(2x-3)(2x-3)=$

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Algebra 1

Multiply two binomials: special cases

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Q. Expand. If necessary, combine like terms.

\newline

(2x-3)(2x-3)=

Recognize the pattern: Recognize the pattern. $\newline$ The expression $(2x-3)(2x-3)$ is in the form of $(a-b)(a-b)$ , which is a special case of the binomial product. $\newline$ Special case: $(a-b)(a-b) = a^2 - 2ab + b^2$
Identify the values of $a$ and $b$ : Identify the values of $a$ and $b$ . $\newline$ Compare $($ $2$ x $-3$ )( $2$ x $-3$ ) with $(a-b)(a-b)$ . $\newline$ $a =$ $2$ x $\newline$ $b =$ $3$
Apply the binomial product formula: Apply the binomial product formula. $\newline$ Using the formula $(a-b)(a-b) = a^2 - 2ab + b^2$ , we expand $(2x-3)(2x-3)$ . $\newline$ $(2x-3)(2x-3) = (2x)^2 - 2(2x)(3) + (3)^2$
Perform the calculations: Perform the calculations. $\newline$ $(2x)^2 - 2(2x)(3) + (3)^2$ $\newline$ $= 4x^2 - 2(6x) + 9$ $\newline$ $= 4x^2 - 12x + 9$