Expand. If necessary, combine like terms. (1+6x)(1-6x)=

Recognize as difference of squares: Recognize the given expression as a difference of squares. The expression (1+6x)(1-6x) is a product of two binomials that are conjugates of each other. The difference of squares formula is a^2 - b^2 = (a+b)(a-b). Here, a is 1 and b is 6x.Apply formula: Apply the difference of squares formula. Using the formula, we can expand the expression as follows: (1+6x)(1-6x) = 1^2 - (6x)^2Calculate squares: Calculate the squares of 1 and 6x. 1^2 = 1 and (6x)^2 = 36x^2 So, the expanded form is: 1 - 36x^2Write final answer: Write the final answer. The expanded form of the expression (1+6x)(1-6x) is 1 - 36x^2.

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Expand.
If necessary, combine like terms.

(1+6x)(1-6x)=

Expand. $\newline$ If necessary, combine like terms. $\newline$ $(1+6x)(1-6x)=$

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Algebra 1

Multiply two binomials: special cases

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Q. Expand.

\newline

If necessary, combine like terms.

\newline

(1+6x)(1-6x)=

Recognize as difference of squares: Recognize the given expression as a difference of squares. $\newline$ The expression $(1+6x)(1-6x)$ is a product of two binomials that are conjugates of each other. The difference of squares formula is $a^2 - b^2 = (a+b)(a-b)$ . Here, $a$ is $1$ and $b$ is $6x$ .
Apply formula: Apply the difference of squares formula. $\newline$ Using the formula, we can expand the expression as follows: $\newline$ $(1+6x)(1-6x) = 1^2 - (6x)^2$
Calculate squares: Calculate the squares of $1$ and $6x$ . $\newline$ $1^2 = 1$ and $(6x)^2 = 36x^2$ $\newline$ So, the expanded form is: $\newline$ $1 - 36x^2$
Write final answer: Write the final answer. $\newline$ The expanded form of the expression $(1+6x)(1-6x)$ is $1 - 36x^2$ .