Q. Divide the polynomials.The form of your answer should either be p(x) or p(x)+x−2k where p(x) is a polynomial and k is an integer.x−2x3+6x2−5x=
Set up long division: Set up the long division.We will use long division to divide the polynomial (x3+6x2−5x) by (x−2).
Divide first term: Divide the first term of the dividend by the first term of the divisor.Divide x3 by x to get x2.Write x2 above the division bar.
Multiply and subtract: Multiply the divisor (x−2) by the result from the previous step (x2).(x−2)×x2=x3−2x2.Subtract this from the dividend.
Perform subtraction: Perform the subtraction. (x3+6x2−5x)−(x3−2x2)=8x2−5x. Bring down the next term to continue the division.
Divide new dividend: Divide the first term of the new dividend (8x2) by the first term of the divisor (x).Divide 8x2 by x to get 8x.Write 8x above the division bar next to x2.
Multiply and subtract: Multiply the divisor (x−2) by the result from the previous step (8x).(x−2)⋅8x=8x2−16x.Subtract this from the new dividend.
Perform subtraction: Perform the subtraction.(8x2−5x)−(8x2−16x)=11x.Bring down the next term if there is any, but since there are no more terms, we proceed to the next step.
Divide new dividend: Divide the first term of the new dividend (11x) by the first term of the divisor (x).Divide 11x by x to get 11.Write 11 above the division bar next to 8x.
Multiply and subtract: Multiply the divisor (x−2) by the result from the previous step 11.(x−2)×11=11x−22.Subtract this from the new dividend.
Perform subtraction: Perform the subtraction.(11x)−(11x−22)=22.This is the remainder since it is of lower degree than the divisor (x−2).
Write final answer: Write the final answer.The quotient is x2+8x+11 with a remainder of 22.The final answer in the form p(x)+x−2k is:p(x)=x2+8x+11k=22
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