Determine the intercepts of the line. Do not round your answers. 8x-5y=-11 x-intercept: (◻,◻) y-intercept: (◻,◻)

Finding the x-intercept: To find the x-intercept, we set y to 0 and solve for x. 8x - 5(0) = -11 8x = -11 x = -11 / 8Finding the y-intercept: The x-intercept is the point where the line crosses the x-axis, so the y-coordinate is 0. Therefore, the x-intercept is (-11/8, 0).To find the y-intercept, we set x to 0 and solve for y. 8(0) - 5y = -11 -5y = -11 y = -11 / -5 y = 11 / 5The y-intercept is the point where the line crosses the y-axis, so the x-coordinate is 0. Therefore, the y-intercept is (0, 11/5).

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Determine the intercepts of the line.
Do not round your answers.

8x-5y=-11

x-intercept:
(◻,◻)

y-intercept:
(◻,◻)

Determine the intercepts of the line. $\newline$ Do not round your answers. $\newline$ $8x-5y=-11$ $\newline$ x-intercept: $\newline$ $(\square,\square)$ $\newline$ y-intercept: $\newline$ $(\square,\square)$

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Math Problems

Algebra 1

Standard form: find x- and y-intercepts

Full solution

Q. Determine the intercepts of the line.

\newline

Do not round your answers.

\newline

8x-5y=-11

\newline

x-intercept:

\newline

(\square,\square)

\newline

y-intercept:

\newline

(\square,\square)

Finding the x-intercept: To find the x-intercept, we set $y$ to $0$ and solve for $x$ . $8x - 5(0) = -11$ $8x = -11$ $x = \frac{-11}{8}$
Finding the y-intercept: The x-intercept is the point where the line crosses the x-axis, so the y-coordinate is $0$ . $\newline$ Therefore, the x-intercept is $\left(-\frac{11}{8}, 0\right)$ .
Finding the y-intercept: The x-intercept is the point where the line crosses the x-axis, so the y-coordinate is $0$ . $\newline$ Therefore, the x-intercept is $(-\frac{11}{8}, 0)$ .To find the y-intercept, we set $x$ to $0$ and solve for $y$ . $\newline$ $8(0) - 5y = -11$ $\newline$ $-5y = -11$ $\newline$ $y = \frac{-11}{-5}$ $\newline$ $y = \frac{11}{5}$
Finding the y-intercept: The x-intercept is the point where the line crosses the x-axis, so the y-coordinate is $0$ . $\newline$ Therefore, the x-intercept is $(-\frac{11}{8}, 0)$ .To find the y-intercept, we set $x$ to $0$ and solve for $y$ . $\newline$ $8(0) - 5y = -11$ $\newline$ $-5y = -11$ $\newline$ $y = \frac{-11}{-5}$ $\newline$ $y = \frac{11}{5}$ The y-intercept is the point where the line crosses the y-axis, so the x-coordinate is $0$ . $\newline$ Therefore, the y-intercept is $(-\frac{11}{8}, 0)$ $0$ .