Determine the intercepts of the line. Do not round your answers. y=-3x+12 y-intercept: (◻,◻) x-intercept: (◻,◻)

Finding the y-intercept: To find the y-intercept, we set x to 0 and solve for y. y = -3(0) + 12 y = 12 The y-intercept is the point where the line crosses the y-axis, so the x-coordinate is 0. Therefore, the y-intercept is (0, 12).Finding the x-intercept: To find the x-intercept, we set y to 0 and solve for x. 0 = -3x + 12 -3x = -12 x = -12 / -3 x = 4 The x-intercept is the point where the line crosses the x-axis, so the y-coordinate is 0. Therefore, the x-intercept is (4, 0).

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Determine the intercepts of the line.
Do not round your answers.

y=-3x+12

y-intercept:
(◻,◻)

x-intercept:
(◻,◻)

Determine the intercepts of the line. $\newline$ Do not round your answers. $\newline$ $y=-3x+12$ $\newline$ y-intercept: $\newline$ $(\square,\square)$ $\newline$ x-intercept: $\newline$ $(\square,\square)$

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Math Problems

Algebra 1

Standard form: find x- and y-intercepts

Full solution

Q. Determine the intercepts of the line.

\newline

Do not round your answers.

\newline

y=-3x+12

\newline

y-intercept:

\newline

(\square,\square)

\newline

x-intercept:

\newline

(\square,\square)

Finding the y-intercept: To find the y-intercept, we set $x$ to $0$ and solve for $y$ . $\newline$ $y = -3(0) + 12$ $\newline$ $y = 12$ $\newline$ The y-intercept is the point where the line crosses the y-axis, so the x-coordinate is $0$ . $\newline$ Therefore, the y-intercept is $(0, 12)$ .
Finding the x-intercept: To find the x-intercept, we set $y$ to $0$ and solve for $x$ .
$0 = -3x + 12$
$-3x = -12$
$x = \frac{-12}{-3}$
$x = 4$
The x-intercept is the point where the line crosses the x-axis, so the y-coordinate is $0$ .
Therefore, the x-intercept is $(4, 0)$ .