Determine the intercepts of the line. Do not round your answers. -5x-4y=10 y-intercept: (◻,◻) x-intercept: (◻,◻)

Find y-intercept: To find the y-intercept, we set x to 0 and solve for y. -5(0) - 4y = 10 -4y = 10Solve for y: Now, divide both sides by -4 to isolate y. -4y / -4 = 10 / -4 y = -10 / 4 y = -5 / 2Find x-intercept: The y-intercept is the point where the line crosses the y-axis, so the x-coordinate is 0. Therefore, the y-intercept is (0, -5/2).Solve for x: To find the x-intercept, we set y to 0 and solve for x. -5x - 4(0) = 10 -5x = 10Now, divide both sides by -5 to isolate x. -5x / -5 = 10 / -5 x = -10 / -5 x = 2The x-intercept is the point where the line crosses the x-axis, so the y-coordinate is 0. Therefore, the x-intercept is (2, 0).

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Determine the intercepts of the line.
Do not round your answers.

-5x-4y=10

y-intercept:
(◻,◻)

x-intercept:
(◻,◻)

Determine the intercepts of the line. $\newline$ Do not round your answers. $\newline$ $-5x-4y=10$ $\newline$ y-intercept: $\newline$ $(0,y)$ $\newline$ x-intercept: $\newline$ $(x,0)$

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Math Problems

Algebra 1

Standard form: find x- and y-intercepts

Full solution

Q. Determine the intercepts of the line.

\newline

Do not round your answers.

\newline

-5x-4y=10

\newline

y-intercept:

\newline

(0,y)

\newline

x-intercept:

\newline

(x,0)

Find y-intercept: To find the y-intercept, we set $x$ to $0$ and solve for $y$ . $\newline$ $-5(0) - 4y = 10$ $\newline$ $-4y = 10$
Solve for y: Now, divide both sides by $-4$ to isolate $y$ .
$\frac{-4y}{-4} = \frac{10}{-4}$
$y = \frac{-10}{4}$
$y = \frac{-5}{2}$
Find x-intercept: The y-intercept is the point where the line crosses the y-axis, so the x-coordinate is $0$ . $\newline$ Therefore, the y-intercept is $(0, -\frac{5}{2})$ .
Solve for x: To find the x-intercept, we set $y$ to $0$ and solve for $x$ .
$-5x - 4(0) = 10$
$-5x = 10$
Solve for x: To find the x-intercept, we set y to $0$ and solve for x. $\newline$ $-5x - 4(0) = 10$ $\newline$ $-5x = 10$ Now, divide both sides by $-5$ to isolate x. $\newline$ $\frac{-5x}{-5} = \frac{10}{-5}$ $\newline$ $x = \frac{-10}{-5}$ $\newline$ $x = 2$
Solve for x: To find the x-intercept, we set y to $0$ and solve for x. $\newline$ $-5x - 4(0) = 10$ $\newline$ $-5x = 10$ Now, divide both sides by $-5$ to isolate x. $\newline$ $-5x / -5 = 10 / -5$ $\newline$ $x = -10 / -5$ $\newline$ $x = 2$ The x-intercept is the point where the line crosses the x-axis, so the y-coordinate is $0$ . $\newline$ Therefore, the x-intercept is $(2, 0)$ .