Determine the intercepts of the line. Do not round your answers. -3x-4=-5y-8 y-intercept: (◻,◻) x-intercept: (◻,◻)

Find y-intercept: Solve for the y-intercept. The y-intercept occurs when x=0. We will substitute x=0 into the equation and solve for y. -3(0)-4=-5y-8 -4=-5y-8 Add 8 to both sides to isolate the term with y. -4 + 8 = -5y 4 = -5y Now, divide both sides by -5 to solve for y. 4 / -5 = y y = -4/5 The y-intercept is at (0, -4/5).Find x-intercept: Solve for the x-intercept. The x-intercept occurs when y=0. We will substitute y=0 into the equation and solve for x. -3x-4=-5(0)-8 -3x-4=-8 Add 4 to both sides to isolate the term with x. -3x = -8 + 4 -3x = -4 Now, divide both sides by -3 to solve for x. x = -4 / -3 x = 4/3 The x-intercept is at (4/3, 0).

Home

Math Problems

Algebra 1

Standard form: find x- and y-intercepts

Full solution

Q. Determine the intercepts of the line.

\newline

Do not round your answers.

\newline

-3x-4=-5y-8

\newline

y-intercept:

\newline

(\square,\square)

\newline

x-intercept:

\newline

(\square,\square)

Find y-intercept: Solve for the y-intercept. $\newline$ The y-intercept occurs when $x=0$ . We will substitute $x=0$ into the equation and solve for $y$ . $\newline$ $-3(0)-4=-5y-8$ $\newline$ $-4=-5y-8$ $\newline$ Add $8$ to both sides to isolate the term with $y$ . $\newline$ $-4 + 8 = -5y$ $\newline$ $4 = -5y$ $\newline$ Now, divide both sides by $-5$ to solve for $y$ . $\newline$ $x=0$ $1$ $\newline$ $x=0$ $2$ $\newline$ The y-intercept is at $x=0$ $3$ .
Find x-intercept: Solve for the x-intercept. $\newline$ The x-intercept occurs when $y=0$ . We will substitute $y=0$ into the equation and solve for $x$ . $\newline$ $-3x-4=-5(0)-8$ $\newline$ $-3x-4=-8$ $\newline$ Add $4$ to both sides to isolate the term with $x$ . $\newline$ $-3x = -8 + 4$ $\newline$ $-3x = -4$ $\newline$ Now, divide both sides by $-3$ to solve for $x$ . $\newline$ $y=0$ $1$ $\newline$ $y=0$ $2$ $\newline$ The x-intercept is at $y=0$ $3$ .