Determine the intercepts of the line. Do not round your answers. y+1=3(x-4) x-intercept: (◻,◻) y-intercept: (◻,◻)

Finding the x-intercept: To find the x-intercept, we set y to 0 and solve for x. y + 1 = 3(x - 4) Substitute y = 0 into the equation. 0 + 1 = 3(x - 4) 1 = 3(x - 4)Solving for x: Now, we solve for x. 1 = 3(x - 4) Divide both sides by 3 to isolate (x - 4). 1 / 3 = x - 4Finding the y-intercept: Next, we add 4 to both sides to solve for x. 1 / 3 + 4 = x x = 4 + 1 / 3 x = 4 + 0.333... x = 4.333... or 4 1/3Solving for y: To find the y-intercept, we set x to 0 and solve for y. y + 1 = 3(x - 4) Substitute x = 0 into the equation. y + 1 = 3(0 - 4) y + 1 = 3(-4) y + 1 = -12Now, we solve for y. y + 1 = -12 Subtract 1 from both sides to isolate y. y = -12 - 1 y = -13

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Determine the intercepts of the line.
Do not round your answers.

y+1=3(x-4)

x-intercept:
(◻,◻)

y-intercept:
(◻,◻)

Determine the intercepts of the line. $\newline$ Do not round your answers. $\newline$ $y+1=3(x-4)$ $\newline$ x-intercept: $\newline$ $(\square,\square)$ $\newline$ y-intercept: $\newline$ $(\square,\square)$

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Math Problems

Algebra 1

Standard form: find x- and y-intercepts

Full solution

Q. Determine the intercepts of the line.

\newline

Do not round your answers.

\newline

y+1=3(x-4)

\newline

x-intercept:

\newline

(\square,\square)

\newline

y-intercept:

\newline

(\square,\square)

Finding the x-intercept: To find the x-intercept, we set $y$ to $0$ and solve for $x$ .
$y + 1 = 3(x - 4)$
Substitute $y = 0$ into the equation.
$0 + 1 = 3(x - 4)$
$1 = 3(x - 4)$
Solving for x: Now, we solve for x. $\newline$ $1 = 3(x - 4)$ $\newline$ Divide both sides by $3$ to isolate $(x - 4)$ . $\newline$ $\frac{1}{3} = x - 4$
Finding the y-intercept: Next, we add $4$ to both sides to solve for x. $\newline$ $\frac{1}{3} + 4 = x$ $\newline$ $x = 4 + \frac{1}{3}$ $\newline$ $x = 4 + 0.333...$ $\newline$ $x = 4.333...$ or $4 \frac{1}{3}$
Solving for y: To find the y-intercept, we set $x$ to $0$ and solve for $y$ . $\newline$ $y + 1 = 3(x - 4)$ $\newline$ Substitute $x = 0$ into the equation. $\newline$ $y + 1 = 3(0 - 4)$ $\newline$ $y + 1 = 3(-4)$ $\newline$ $y + 1 = -12$
Solving for y: To find the y-intercept, we set x to $0$ and solve for y. $\newline$ $y + 1 = 3(x - 4)$ $\newline$ Substitute $x = 0$ into the equation. $\newline$ $y + 1 = 3(0 - 4)$ $\newline$ $y + 1 = 3(-4)$ $\newline$ $y + 1 = -12$ Now, we solve for y. $\newline$ $y + 1 = -12$ $\newline$ Subtract $1$ from both sides to isolate y. $\newline$ $y = -12 - 1$ $\newline$ $y = -13$