Determine the intercepts of the line. Do not round your answers. -4x+7=2y-3 y-intercept: (◻,◻) x-intercept: (◻,◻)

Find y-intercept: To find the y-intercept, we set x to 0 and solve for y. -4(0) + 7 = 2y - 3 7 = 2y - 3 Add 3 to both sides to isolate the term with y. 7 + 3 = 2y 10 = 2y Divide both sides by 2 to solve for y. y = 10 / 2 y = 5 The y-intercept is at (0, 5).Solve for y: To find the x-intercept, we set y to 0 and solve for x. -4x + 7 = 2(0) - 3 -4x + 7 = -3 Subtract 7 from both sides to isolate the term with x. -4x = -3 - 7 -4x = -10 Divide both sides by -4 to solve for x. x = -10 / -4 x = 5 / 2 The x-intercept is at (5/2, 0).

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Math Problems

Algebra 1

Standard form: find x- and y-intercepts

Full solution

Q. Determine the intercepts of the line.

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Do not round your answers.

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-4x+7=2y-3

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y-intercept:

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(\square,\square)

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x-intercept:

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(\square,\square)

Find y-intercept: To find the y-intercept, we set $x$ to $0$ and solve for $y$ . $\newline$ $-4(0) + 7 = 2y - 3$ $\newline$ $7 = 2y - 3$ $\newline$ Add $3$ to both sides to isolate the term with $y$ . $\newline$ $7 + 3 = 2y$ $\newline$ $10 = 2y$ $\newline$ Divide both sides by $2$ to solve for $y$ . $\newline$ $y = \frac{10}{2}$ $\newline$ $y = 5$ $\newline$ The y-intercept is at $(0, 5)$ .
Solve for y: To find the x-intercept, we set y to $0$ and solve for x. $\newline$ $-4x + 7 = 2(0) - 3$ $\newline$ $-4x + 7 = -3$ $\newline$ Subtract $7$ from both sides to isolate the term with x. $\newline$ $-4x = -3 - 7$ $\newline$ $-4x = -10$ $\newline$ Divide both sides by $-4$ to solve for x. $\newline$ $x = \frac{-10}{-4}$ $\newline$ $x = \frac{5}{2}$ $\newline$ The x-intercept is at $(\frac{5}{2}, 0)$ .