Determine the intercepts of the line. Do not round your answers. y=10 x-32 y-intercept: (◻,◻) x-intercept: (◻,◻)

Finding the y-intercept: To find the y-intercept, we set x to 0 and solve for y. y = 10(0) - 32 y = -32 The y-intercept is the point where the line crosses the y-axis, which occurs when x=0. Therefore, the y-intercept is at (0, -32).Finding the x-intercept: To find the x-intercept, we set y to 0 and solve for x. 0 = 10x - 32 10x = 32 x = 32 / 10 x = 3.2 The x-intercept is the point where the line crosses the x-axis, which occurs when y=0. Therefore, the x-intercept is at (3.2, 0).

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Determine the intercepts of the line.
Do not round your answers.

y=10 x-32

y-intercept:
(◻,◻)

x-intercept:
(◻,◻)

Determine the intercepts of the line. $\newline$ Do not round your answers. $\newline$ $y=10x-32$ $\newline$ y-intercept: $\newline$ $(\square,\square)$ $\newline$ x-intercept: $\newline$ $(\square,\square)$

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Math Problems

Algebra 1

Standard form: find x- and y-intercepts

Full solution

Q. Determine the intercepts of the line.

\newline

Do not round your answers.

\newline

y=10x-32

\newline

y-intercept:

\newline

(\square,\square)

\newline

x-intercept:

\newline

(\square,\square)

Finding the y-intercept: To find the y-intercept, we set $x$ to $0$ and solve for $y$ . $\newline$ $y = 10(0) - 32$ $\newline$ $y = -32$ $\newline$ The y-intercept is the point where the line crosses the y-axis, which occurs when $x=0$ . Therefore, the y-intercept is at $(0, -32)$ .
Finding the x-intercept: To find the x-intercept, we set $y$ to $0$ and solve for $x$ . $\newline$ $0 = 10x - 32$ $\newline$ $10x = 32$ $\newline$ $x = \frac{32}{10}$ $\newline$ $x = 3.2$ $\newline$ The x-intercept is the point where the line crosses the x-axis, which occurs when $y=0$ . Therefore, the x-intercept is at $(3.2, 0)$ .