Determine the intercepts of the line. Do not round your answers. -6x+3y=-7 x-intercept: (◻,◻) y-intercept: (◻,◻)

Finding the x-intercept: To find the x-intercept, we set y to 0 and solve for x. -6x + 3(0) = -7 -6x = -7 x = -7 / -6 x = 7 / 6 The x-intercept is at (7/6, 0).Finding the y-intercept: To find the y-intercept, we set x to 0 and solve for y. -6(0) + 3y = -7 3y = -7 y = -7 / 3 The y-intercept is at (0, -7/3).

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Determine the intercepts of the line.
Do not round your answers.

-6x+3y=-7

x-intercept:
(◻,◻)

y-intercept:
(◻,◻)

Determine the intercepts of the line. $\newline$ Do not round your answers. $\newline$ $-6x+3y=-7$ $\newline$ x-intercept: $\newline$ $(\square,\square)$ $\newline$ y-intercept: $\newline$ $(\square,\square)$

View step-by-step help

Home

Math Problems

Algebra 1

Standard form: find x- and y-intercepts

Full solution

Q. Determine the intercepts of the line.

\newline

Do not round your answers.

\newline

-6x+3y=-7

\newline

x-intercept:

\newline

(\square,\square)

\newline

y-intercept:

\newline

(\square,\square)

Finding the x-intercept: To find the x-intercept, we set $y$ to $0$ and solve for $x$ .
$-6x + 3(0) = -7$
$-6x = -7$
$x = \frac{-7}{-6}$
$x = \frac{7}{6}$
The x-intercept is at $(\frac{7}{6}, 0)$ .
Finding the y-intercept: To find the y-intercept, we set $x$ to $0$ and solve for $y$ . $\newline$ $-6(0) + 3y = -7$ $\newline$ $3y = -7$ $\newline$ $y = \frac{-7}{3}$ $\newline$ The y-intercept is at $(0, \frac{-7}{3})$ .