Determine the intercepts of the line. Do not round your answers. y=6x+13 x-intercept: (◻,◻) y-intercept: (◻,◻)

Finding the x-intercept: To find the x-intercept, we set y to 0 and solve for x. y = 6x + 13 0 = 6x + 13 Subtract 13 from both sides to isolate the term with x. -13 = 6x Now divide both sides by 6 to solve for x. x = -13 / 6Finding the y-intercept: The x-intercept is the point where the line crosses the x-axis, so the y-coordinate is 0. Therefore, the x-intercept is (-13/6, 0).To find the y-intercept, we set x to 0 and solve for y. y = 6x + 13 y = 6(0) + 13 y = 0 + 13 y = 13The y-intercept is the point where the line crosses the y-axis, so the x-coordinate is 0. Therefore, the y-intercept is (0, 13).

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Determine the intercepts of the line.
Do not round your answers.

y=6x+13

x-intercept:
(◻,◻)

y-intercept:
(◻,◻)

Determine the intercepts of the line. $\newline$ Do not round your answers. $\newline$ $y=6x+13$ $\newline$ x-intercept: $\newline$ $(\square,\square)$ $\newline$ y-intercept: $\newline$ $(\square,\square)$

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Math Problems

Algebra 1

Standard form: find x- and y-intercepts

Full solution

Q. Determine the intercepts of the line.

\newline

Do not round your answers.

\newline

y=6x+13

\newline

x-intercept:

\newline

(\square,\square)

\newline

y-intercept:

\newline

(\square,\square)

Finding the x-intercept: To find the x-intercept, we set $y$ to $0$ and solve for $x$ .
$y = 6x + 13$
$0 = 6x + 13$
Subtract $13$ from both sides to isolate the term with $x$ .
$-13 = 6x$
Now divide both sides by $6$ to solve for $x$ .
$0$ $0$
Finding the y-intercept: The x-intercept is the point where the line crosses the x-axis, so the y-coordinate is $0$ . $\newline$ Therefore, the x-intercept is $(-\frac{13}{6}, 0)$ .
Finding the y-intercept: The x-intercept is the point where the line crosses the x-axis, so the y-coordinate is $0$ . $\newline$ Therefore, the x-intercept is $(-\frac{13}{6}, 0)$ .To find the y-intercept, we set $x$ to $0$ and solve for $y$ . $\newline$ $y = 6x + 13$ $\newline$ $y = 6(0) + 13$ $\newline$ $y = 0 + 13$ $\newline$ $y = 13$
Finding the y-intercept: The x-intercept is the point where the line crosses the x-axis, so the y-coordinate is $0$ . Therefore, the x-intercept is $\left(-\frac{13}{6}, 0\right)$ . To find the y-intercept, we set $x$ to $0$ and solve for $y$ . $y = 6x + 13$ $y = 6(0) + 13$ $y = 0 + 13$ $y = 13$ The y-intercept is the point where the line crosses the y-axis, so the x-coordinate is $0$ . Therefore, the y-intercept is $(0, 13)$ .