Determine the intercepts of the line. Do not round your answers. y-6=4(x+5) y-intercept: (◻,◻) x-intercept: (◻,◻)

Finding the y-intercept: To find the y-intercept, we set x to 0 and solve for y. Substitute x = 0 into the equation y - 6 = 4(x + 5). y - 6 = 4(0 + 5) y - 6 = 20 y = 20 + 6 y = 26 The y-intercept is at (0, 26).Substituting x = 0: To find the x-intercept, we set y to 0 and solve for x. Substitute y = 0 into the equation y - 6 = 4(x + 5). 0 - 6 = 4(x + 5) -6 = 4x + 20 4x = -6 - 20 4x = -26 x = -26 / 4 x = -13 / 2 The x-intercept is at (-13/2, 0).

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Determine the intercepts of the line.
Do not round your answers.

y-6=4(x+5)

y-intercept:
(◻,◻)

x-intercept:
(◻,◻)

Determine the intercepts of the line. $\newline$ Do not round your answers. $\newline$ $y-6=4(x+5)$ $\newline$ y-intercept: $\newline$ $(\square,\square)$ $\newline$ x-intercept: $\newline$ $(\square,\square)$

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Math Problems

Algebra 1

Standard form: find x- and y-intercepts

Full solution

Q. Determine the intercepts of the line.

\newline

Do not round your answers.

\newline

y-6=4(x+5)

\newline

y-intercept:

\newline

(\square,\square)

\newline

x-intercept:

\newline

(\square,\square)

Finding the y-intercept: To find the y-intercept, we set $x$ to $0$ and solve for $y$ . $\newline$ Substitute $x = 0$ into the equation $y - 6 = 4(x + 5)$ . $\newline$ $y - 6 = 4(0 + 5)$ $\newline$ $y - 6 = 20$ $\newline$ $y = 20 + 6$ $\newline$ $y = 26$ $\newline$ The y-intercept is at $(0, 26)$ .
Substituting $x = 0$ : To find the x-intercept, we set $y$ to $0$ and solve for $x$ . $\newline$ Substitute $y = 0$ into the equation $y - 6 = 4(x + 5)$ . $\newline$ $0 - 6 = 4(x + 5)$ $\newline$ $-6 = 4x + 20$ $\newline$ $4x = -6 - 20$ $\newline$ $4x = -26$ $\newline$ $y$ $0$ $\newline$ $y$ $1$ $\newline$ The x-intercept is at $y$ $2$ .