Determine the intercepts of the line. Do not round your answers. -7x-6y=-15 y-intercept: (◻,◻) x-intercept: (◻,◻)

Finding the y-intercept: To find the y-intercept, we set x to 0 and solve for y. -7(0) - 6y = -15 -6y = -15 y = -15 / -6 y = 5 / 2 The y-intercept is at (0, 5/2).Finding the x-intercept: To find the x-intercept, we set y to 0 and solve for x. -7x - 6(0) = -15 -7x = -15 x = -15 / -7 x = 15 / 7 The x-intercept is at (15/7, 0).

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Determine the intercepts of the line.
Do not round your answers.

-7x-6y=-15

y-intercept:
(◻,◻)

x-intercept:
(◻,◻)

Determine the intercepts of the line. $\newline$ Do not round your answers. $\newline$ $-7x-6y=-15$ $\newline$ y-intercept: $\newline$ $(\square,\square)$ $\newline$ x-intercept: $\newline$ $(\square,\square)$

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Math Problems

Algebra 1

Standard form: find x- and y-intercepts

Full solution

Q. Determine the intercepts of the line.

\newline

Do not round your answers.

\newline

-7x-6y=-15

\newline

y-intercept:

\newline

(\square,\square)

\newline

x-intercept:

\newline

(\square,\square)

Finding the y-intercept: To find the y-intercept, we set $x$ to $0$ and solve for $y$ . $\newline$ $-7(0) - 6y = -15$ $\newline$ $-6y = -15$ $\newline$ $y = \frac{-15}{-6}$ $\newline$ $y = \frac{5}{2}$ $\newline$ The y-intercept is at $(0, \frac{5}{2})$ .
Finding the x-intercept: To find the x-intercept, we set $y$ to $0$ and solve for $x$ .
$-7x - 6(0) = -15$
$-7x = -15$
$x = \frac{-15}{-7}$
$x = \frac{15}{7}$
The x-intercept is at $(\frac{15}{7}, 0)$ .