Determine the intercepts of the line. Do not round your answers. -4x+7y=3 x-intercept: (◻,◻) y-intercept: (◻,◻)

Finding the x-intercept: To find the x-intercept, we set y to 0 and solve for x. -4x + 7(0) = 3 -4x = 3 x = 3 / -4 x = -3/4 The x-intercept is at (-3/4, 0).Finding the y-intercept: To find the y-intercept, we set x to 0 and solve for y. -4(0) + 7y = 3 7y = 3 y = 3 / 7 The y-intercept is at (0, 3/7).

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Determine the intercepts of the line.
Do not round your answers.

-4x+7y=3

x-intercept:
(◻,◻)

y-intercept:
(◻,◻)

Determine the intercepts of the line. $\newline$ Do not round your answers. $\newline$ $-4x+7y=3$ $\newline$ x-intercept: $\newline$ $(\square,\square)$ $\newline$ y-intercept: $\newline$ $(\square,\square)$

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Math Problems

Algebra 1

Standard form: find x- and y-intercepts

Full solution

Q. Determine the intercepts of the line.

\newline

Do not round your answers.

\newline

-4x+7y=3

\newline

x-intercept:

\newline

(\square,\square)

\newline

y-intercept:

\newline

(\square,\square)

Finding the x-intercept: To find the x-intercept, we set $y$ to $0$ and solve for $x$ .
$-4x + 7(0) = 3$
$-4x = 3$
$x = \frac{3}{-4}$
$x = -\frac{3}{4}$
The x-intercept is at $(-\frac{3}{4}, 0)$ .
Finding the y-intercept: To find the y-intercept, we set $x$ to $0$ and solve for $y$ .
$-4(0) + 7y = 3$
$7y = 3$
$y = \frac{3}{7}$
The y-intercept is at $(0, \frac{3}{7})$ .