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Complete the point-slope equation of the line through 
(-5,4) and 
(1,6).
Use exact numbers.

y-6=

Complete the point-slope equation of the line through (5,4)(-5,4) and (1,6)(1,6).\newlineUse exact numbers.\newliney6=y-6=

Full solution

Q. Complete the point-slope equation of the line through (5,4)(-5,4) and (1,6)(1,6).\newlineUse exact numbers.\newliney6=y-6=
  1. Calculate the slope: To find the point-slope form of the equation of the line, we first need to calculate the slope (m) of the line using the two given points (5-5,44) and (11,66). The slope is given by the formula:\newlinem=y2y1x2x1 m = \frac{y_2 - y_1}{x_2 - x_1}
  2. Substitute coordinates into slope formula: Substitute the coordinates of the points into the slope formula:\newlinem=641(5) m = \frac{6 - 4}{1 - (-5)} \newlinem=26 m = \frac{2}{6} \newlinem=13 m = \frac{1}{3} \newlineThe slope of the line is 13 \frac{1}{3} .
  3. Find the slope of the line: Now that we have the slope, we can use the point-slope form of the equation of a line, which is:\newlineyy1=m(xx1) y - y_1 = m(x - x_1) \newlineWe can use either of the two points for (x1,y1) (x_1, y_1) . Let's use the point (11,66).
  4. Use the point-slope form: Substitute the slope and the coordinates of the point (11,66) into the point-slope form:\newliney6=13(x1) y - 6 = \frac{1}{3}(x - 1) \newlineThis is the point-slope equation of the line through the points (5-5,44) and (11,66).

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