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Complete the point-slope equation of the line through 
(-1,6) and 
(1,5).
Use exact numbers.

y-6=

Complete the point-slope equation of the line through (1,6) (-1,6) and (1,5) (1,5) .\newlineUse exact numbers.\newliney6= y-6=

Full solution

Q. Complete the point-slope equation of the line through (1,6) (-1,6) and (1,5) (1,5) .\newlineUse exact numbers.\newliney6= y-6=
  1. Calculate the slope: To find the point-slope form of the equation of the line, we first need to calculate the slope of the line using the two given points (1-1,66) and (11,55). The slope (m) is given by the formula:\newlinem=y2y1x2x1 m = \frac{y_2 - y_1}{x_2 - x_1}
  2. Substitute coordinates into slope formula: Substitute the coordinates of the points into the slope formula:\newlinem=561(1) m = \frac{5 - 6}{1 - (-1)} \newlinem=12 m = \frac{-1}{2} \newlineThe slope of the line is 1-1/22.
  3. Find the slope of the line: Now that we have the slope, we can use the point-slope form of the equation of a line, which is:\newlineyy1=m(xx1) y - y_1 = m(x - x_1) \newlineWe can use either of the two points for (x1,y1) (x_1, y_1) . Let's use the point (1-1,66).
  4. Use the point-slope form: Substitute the slope and the coordinates of the point into the point-slope form:\newliney6=12(x(1)) y - 6 = -\frac{1}{2}(x - (-1)) \newliney6=12(x+1) y - 6 = -\frac{1}{2}(x + 1) \newlineThis is the point-slope equation of the line through the points (1-1,66) and (11,55).

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