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Complete the point-slope equation of the line through 
(1,-1) and 
(5,2).
Use exact numbers.

y-(-1)=

Complete the point-slope equation of the line through (1,1) (1,-1) and (5,2) (5,2) .\newlineUse exact numbers.\newliney(1)= y-(-1)=\square

Full solution

Q. Complete the point-slope equation of the line through (1,1) (1,-1) and (5,2) (5,2) .\newlineUse exact numbers.\newliney(1)= y-(-1)=\square
  1. Find the slope: First, we need to find the slope of the line that passes through the points (11, 1-1) and (55, 22). The slope (m) is given by the formula:\newlinem=y2y1x2x1 m = \frac{y_2 - y_1}{x_2 - x_1}
  2. Calculate the slope: Plugging in the coordinates of the two points into the slope formula, we get:\newlinem=2(1)51 m = \frac{2 - (-1)}{5 - 1} \newlinem=2+151 m = \frac{2 + 1}{5 - 1} \newlinem=34 m = \frac{3}{4} \newlineSo, the slope of the line is 34 \frac{3}{4} .
  3. Use point-slope form: Now that we have the slope, we can use the point-slope form of the equation of a line, which is:\newlineyy1=m(xx1) y - y_1 = m(x - x_1) \newlinewhere (x1,y1) (x_1, y_1) is a point on the line (we can use either of the given points) and m m is the slope.
  4. Substitute values: Using the point (11, 1-1) and the slope 34 \frac{3}{4} , we substitute into the point-slope form:\newliney(1)=34(x1) y - (-1) = \frac{3}{4}(x - 1) \newlineThis simplifies to:\newliney+1=34(x1) y + 1 = \frac{3}{4}(x - 1)
  5. Final point-slope equation: We can leave the equation in this form, as the problem asks for the point-slope equation with exact numbers. Therefore, the final point-slope equation of the line is:\newliney+1=34(x1) y + 1 = \frac{3}{4}(x - 1)

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