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Complete the equation of the line through 
(-1,6) and 
(7,-2). Use exact numbers.

y=

Complete the equation of the line through (1,6) (-1,6) and (7,2) (7,-2) .\newlineUse exact numbers.\newliney= y=\square

Full solution

Q. Complete the equation of the line through (1,6) (-1,6) and (7,2) (7,-2) .\newlineUse exact numbers.\newliney= y=\square
  1. Calculate Slope: To find the equation of a line, we need to determine the slope mm of the line using the formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}, where (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) are the coordinates of the two points the line passes through.\newlineLet's calculate the slope using the points (1,6)(-1,6) and (7,2)(7,-2).\newlinem=267(1)=88=1m = \frac{-2 - 6}{7 - (-1)} = \frac{-8}{8} = -1
  2. Use Point-Slope Form: Now that we have the slope, we can use the point-slope form of the equation of a line, which is yy1=m(xx1)y - y_1 = m(x - x_1), where mm is the slope and (x1,y1)(x_1, y_1) is a point on the line.\newlineLet's use the point (1,6)(-1,6) and the slope 1-1 to write the equation.\newliney6=1(x(1))y - 6 = -1(x - (-1))
  3. Simplify Equation: Simplify the equation by distributing the slope 1-1 into the parentheses.\newliney6=1(x+1)y - 6 = -1(x + 1)\newliney6=1x1y - 6 = -1x - 1
  4. Isolate y: To write the equation in slope-intercept form y=mx+by = mx + b, we need to isolate yy on one side of the equation.\newlineAdd 66 to both sides of the equation to isolate yy.\newliney=1x1+6y = -1x - 1 + 6\newliney=1x+5y = -1x + 5
  5. Final Equation: The equation of the line in slope-intercept form is now y=1x+5y = -1x + 5, which can also be written as y=x+5y = -x + 5. This is the final answer in standard form with a leading coefficient of 11 for xx.

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