An object is launched from a platform. Its height (in meters), x seconds after the launch, is modeled by: h(x)=-5(x-4)^(2)+180 What is the height of the object at the time of launch? meters

Identify Launch Time: Identify the time of launch. The time of launch is when x = 0 seconds, since x represents the time after the launch.Substitute x=0: Substitute x = 0 into the height equation. h(x) = -5(x-4)² + 180 h(0) = -5(0-4)² + 180Calculate Launch Height: Calculate the height at the time of launch. h(0) = -5(-4)² + 180 h(0) = -5(16) + 180 h(0) = -80 + 180 h(0) = 100

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An object is launched from a platform.
Its height (in meters),
x seconds after the launch, is modeled by:

h(x)=-5(x-4)^(2)+180
What is the height of the object at the time of launch?
meters

An object is launched from a platform. Its height (in meters), $x$ seconds after the launch, is modeled by: $\newline$ $h(x)=-5(x-4)^{2}+180$ $\newline$ What is the height of the object at the time of launch? $\text{meters}$

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Q. An object is launched from a platform. Its height (in meters),

x

seconds after the launch, is modeled by:

\newline

h(x)=-5(x-4)^{2}+180

\newline

What is the height of the object at the time of launch?

\text{meters}

Identify Launch Time: Identify the time of launch. $\newline$ The time of launch is when $x = 0$ seconds, since $x$ represents the time after the launch.
Substitute $x=0$ : Substitute $x = 0$ into the height equation. $\newline$ $h(x) = -5(x-4)^2 + 180$ $\newline$ $h(0) = -5(0-4)^2 + 180$
Calculate Launch Height: Calculate the height at the time of launch. $\newline$ $h(0) = -5(-4)^2 + 180$ $\newline$ $h(0) = -5(16) + 180$ $\newline$ $h(0) = -80 + 180$ $\newline$ $h(0) = 100$