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An object is launched from a platform.
Its height (in meters), 
x seconds after the launch, is modeled by

h(x)=-5(x+1)(x-9)
What is the height of the object at the time of launch?
meters

An object is launched from a platform. Its height (in meters), xx seconds after the launch, is modeled by\newlineh(x)=5(x+1)(x9)h(x)=-5(x+1)(x-9)\newlineWhat is the height of the object at the time of launch? meters\text{meters}

Full solution

Q. An object is launched from a platform. Its height (in meters), xx seconds after the launch, is modeled by\newlineh(x)=5(x+1)(x9)h(x)=-5(x+1)(x-9)\newlineWhat is the height of the object at the time of launch? meters\text{meters}
  1. Step 11: Evaluate h(x)h(x) at x=0x = 0: To find the height of the object at the time of launch, we need to evaluate the function h(x)h(x) at x=0x = 0, since the time of launch corresponds to the initial time, which is 00 seconds after the launch.\newlineCalculation: h(0)=5(0+1)(09)h(0) = -5(0 + 1)(0 - 9)
  2. Step 22: Substitute x=0x = 0 into the function: Now, we substitute x=0x = 0 into the function and simplify the expression to find the height at launch.\newlineCalculation: h(0)=5(1)(9)=5×9=45h(0) = -5(1)(-9) = -5 \times -9 = 45
  3. Step 33: Simplify the expression: The height of the object at the time of launch is 4545 meters.

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