An intermediate chemical is formed during a chemical reaction. Assuming the mass is positive, the mass of the intermediate chemical, m, in grams t milliseconds after mixing the initial chemicals is given by: m=-18.79(t-3.68)(t-7.58 According to the model, how long did the intermediate chemical have positive mass? Round your answer to the nearest tenth of a millisecond.

Question

An intermediate chemical is formed during a chemical reaction. Assuming the mass is positive, the mass of the intermediate chemical,  m, in grams  t milliseconds after mixing the initial chemicals is given by:  m=-18.79(t-3.68)(t-7.58 According to the model, how long did the intermediate chemical have positive mass? Round your answer to the nearest tenth of a millisecond.

Bytelearn · Accepted Answer

Given equation for mass: We are given the equation for the mass of the intermediate chemical as a function of time: m = -18.79(t - 3.68)(t - 7.58). To find out how long the intermediate chemical had a positive mass, we need to determine the interval of time during which the mass m is positive.Determining positive mass interval: The mass m will be positive when the factors (t - 3.68) and (t - 7.58) have the same sign, either both positive or both negative. Since we are assuming the mass is positive, we are looking for the time interval where t is between 3.68 and 7.58 milliseconds.Calculating time duration: To find the duration for which the mass is positive, we subtract the lower time limit from the upper time limit: 7.58 ms - 3.68 ms.Rounding the duration: Performing the subtraction gives us the duration: 7.58 - 3.68 = 3.9 milliseconds.We round the duration to the nearest tenth of a millisecond, which in this case does not require any rounding since 3.9 is already at one decimal place.

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