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Alain throws a stone off a bridge into a river below. The stone's height (in meters above the water), x seconds after Alain threw it, is modeled by: h(x)=-5x^(2)+10 x+15 What is the height of the stone at the time it is thrown? meters

Alain throws a stone off a bridge into a river below. The stone's height (in meters above the water), x x seconds after Alain threw it, is modeled by:\newlineh(x)=−5x2+10x+15 h(x) = -5x^2 + 10x + 15 \newlineWhat is the height of the stone at the time it is thrown?\newlinemeters \text{meters}

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Q. Alain throws a stone off a bridge into a river below. The stone's height (in meters above the water), x x seconds after Alain threw it, is modeled by:\newlineh(x)=−5x2+10x+15 h(x) = -5x^2 + 10x + 15 \newlineWhat is the height of the stone at the time it is thrown?\newlinemeters \text{meters}
  1. Evaluate height function: To find the height of the stone at the time it is thrown, we need to evaluate the height function h(x)h(x) at the time x=0x = 0, which is the moment the stone is thrown.\newlineCalculation: h(0)=−5(0)2+10(0)+15h(0) = -5(0)^2 + 10(0) + 15
  2. Simplify expression: Simplifying the expression, we get:\newlineh(0)=−5(0)+10(0)+15h(0) = -5(0) + 10(0) + 15\newlineh(0)=0+0+15h(0) = 0 + 0 + 15\newlineh(0)=15h(0) = 15

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