Ajay is researching how the population of his hometown has changed over time. Specifically, he learns his hometown had a population of 20,000 in 1990 , and that the population has since increased by about 8% every 3 years.Ajay predicts that his town can only support a population of 50,000 .Ajay is relieved to see that population has not exceeded 50,000t years after 1990 .Write an inequality in terms of t that models the situation.
Q. Ajay is researching how the population of his hometown has changed over time. Specifically, he learns his hometown had a population of 20,000 in 1990 , and that the population has since increased by about 8% every 3 years.Ajay predicts that his town can only support a population of 50,000 .Ajay is relieved to see that population has not exceeded 50,000t years after 1990 .Write an inequality in terms of t that models the situation.
Identify Population and Growth Rate: Identify the initial population and the growth rate.The initial population P0 in 1990 is 20,000, and the growth rate is 8% every 3 years.
Convert to Exponential Growth Factor: Convert the growth rate to an exponential growth factor.The growth rate of 8% every 3 years can be expressed as a growth factor (b) of 1+0.08=1.08. However, since the growth happens every 3 years, we need to adjust the exponent to reflect this. The population after t years can be modeled by the equation P(t)=P0⋅b(t/3), where t is the number of years after 1990.
Write Population Inequality: Write the inequality that represents the population not exceeding 50,000.We want to ensure that the population P(t) does not exceed 50,000. Therefore, the inequality will be P(t)≤50,000.
Substitute Values into Inequality: Substitute the values of P0 and b into the inequality.Substituting the values we have, we get 20,000×(1.08)3t≤50,000.
Simplify Final Inequality: Simplify the inequality to its final form.The inequality 20,000×(1.08)(t/3)≤50,000 is already in its simplest form and correctly models the situation.
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