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A large truck, traveling 30 miles per hour, carries a letter from the central post office to the local post office. The letter is then loaded onto a local vehicle, which travels at an average speed of 10 miles per hour, until the letter reaches its destination. The large truck carried the letter for 
a minutes and the local vehicle carried the letter for 
b minutes. If the total distance that the letter travelled from the central post office to its destination was 24 miles, which of the following equations correctly relates 
a and 
b ?
Choose 1 answer:
(A) 
(30)/(60)a+(10)/(60)b=24
(B) 
(60)/(30)a+(60)/(10)b=24
(c) 
30 a+10 b=24
(D) 
60*30 a+60*10 b=24

A large truck, traveling 3030 miles per hour, carries a letter from the central post office to the local post office. The letter is then loaded onto a local vehicle, which travels at an average speed of 1010 miles per hour, until the letter reaches its destination. The large truck carried the letter for a a minutes and the local vehicle carried the letter for b b minutes. If the total distance that the letter travelled from the central post office to its destination was 2424 miles, which of the following equations correctly relates a a and b b ?\newlineChoose 11 answer:\newline(A) 3060a+1060b=24 \frac{30}{60} a+\frac{10}{60} b=24 \newline(B) 6030a+6010b=24 \frac{60}{30} a+\frac{60}{10} b=24 \newline(C) 30a+10b=24 30 a+10 b=24 \newline(D) 6030a+6010b=24 60 \cdot 30 a+60 \cdot 10 b=24

Full solution

Q. A large truck, traveling 3030 miles per hour, carries a letter from the central post office to the local post office. The letter is then loaded onto a local vehicle, which travels at an average speed of 1010 miles per hour, until the letter reaches its destination. The large truck carried the letter for a a minutes and the local vehicle carried the letter for b b minutes. If the total distance that the letter travelled from the central post office to its destination was 2424 miles, which of the following equations correctly relates a a and b b ?\newlineChoose 11 answer:\newline(A) 3060a+1060b=24 \frac{30}{60} a+\frac{10}{60} b=24 \newline(B) 6030a+6010b=24 \frac{60}{30} a+\frac{60}{10} b=24 \newline(C) 30a+10b=24 30 a+10 b=24 \newline(D) 6030a+6010b=24 60 \cdot 30 a+60 \cdot 10 b=24
  1. Convert to Hours: To find the correct equation, we need to convert the time spent by the truck and the local vehicle into hours since the speeds are given in miles per hour (mph). Since there are 6060 minutes in an hour, we divide the time in minutes by 6060 to convert it to hours.
  2. Calculate Truck Distance: For the large truck traveling at 30mph30 \, \text{mph} for aa minutes, the distance covered by the truck is (30miles/hour)×(aminutes/60minutes/hour)=(30/60)a=(1/2)amiles.(30 \, \text{miles/hour}) \times (a \, \text{minutes} / 60 \, \text{minutes/hour}) = (30/60)a = (1/2)a \, \text{miles}.
  3. Calculate Local Vehicle Distance: For the local vehicle traveling at 1010 mph for bb minutes, the distance covered by the vehicle is (10 miles/hour)×(b minutes/60 minutes/hour)=(10/60)b=(1/6)b(10 \text{ miles/hour}) \times (b \text{ minutes} / 60 \text{ minutes/hour}) = (10/60)b = (1/6)b miles.
  4. Total Distance Equation: The total distance covered by both the truck and the local vehicle is the sum of the distances they each covered, which equals 2424 miles. Therefore, the equation relating aa and bb is:\newline rac{1}{2}a + rac{1}{6}b = 24
  5. Simplify Total Distance Equation: To find the correct answer from the given options, we need to simplify the equation (12)a+(16)b=24(\frac{1}{2})a + (\frac{1}{6})b = 24. Multiplying both sides of the equation by 66 to clear the fractions, we get:\newline6(12)a+6(16)b=6246*(\frac{1}{2})a + 6*(\frac{1}{6})b = 6*24\newline3a+b=1443a + b = 144\newlineThis equation is not in the form of any of the given options, which means we need to check our steps for any errors.

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