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A hovercraft takes off from a platform.
Its height (in meters), 
x seconds after takeoff, is modeled by

h(x)=-(x-11)(x+3)
What is the height of the hovercraft at the time of takeoff?
meters

A hovercraft takes off from a platform. Its height (in meters), xx seconds after takeoff, is modeled by\newlineh(x)=(x11)(x+3)h(x) = -(x-11)(x+3)\newlineWhat is the height of the hovercraft at the time of takeoff?\newlinemetersmeters

Full solution

Q. A hovercraft takes off from a platform. Its height (in meters), xx seconds after takeoff, is modeled by\newlineh(x)=(x11)(x+3)h(x) = -(x-11)(x+3)\newlineWhat is the height of the hovercraft at the time of takeoff?\newlinemetersmeters
  1. Takeoff time: The time of takeoff is when x=0x = 0, since xx represents the time in seconds after takeoff. To find the height of the hovercraft at takeoff, we need to evaluate the function h(x)h(x) at x=0x = 0.
  2. Height at takeoff: Substitute x=0x = 0 into the function h(x)h(x) to find the height at takeoff.\newlineh(0)=(011)(0+3)h(0) = -(0 - 11)(0 + 3)
  3. Substitute x=0x = 0: Perform the calculations inside the parentheses first.h(0)=(11×3)h(0) = -(-11 \times 3)
  4. Perform calculations: Multiply the numbers inside the parentheses.\newlineh(0)=(33)h(0) = -(-33)
  5. Multiply numbers: A negative times a negative is a positive, so we simplify the expression. h(0)=33h(0) = 33

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