A cylindrical glass of water is 2.5 centimeters tall and holds a volume of 20 cubic centimeters of water.The radius of the glass is πp centimeters, where p is a constant. What is the value of p ?
Q. A cylindrical glass of water is 2.5 centimeters tall and holds a volume of 20 cubic centimeters of water.The radius of the glass is πp centimeters, where p is a constant. What is the value of p ?
Given Information: The volume V of a cylinder is given by the formula V=πr2h, where r is the radius and h is the height of the cylinder. We are given that the volume V is 20 cubic centimeters and the height h is 2.5 centimeters. We are also given that the radius r is πp centimeters. We need to find the value of p.
Volume Formula Substitution: Substitute the given values into the volume formula: 20=π(πp)2×2.5Simplify the equation by squaring the radius: 20=π(πp)×2.5
Divide and Solve: Cancel out the π in the numerator and denominator: 20=p×2.5Now we have a simple equation to solve for p.
Calculate Value of p: Divide both sides of the equation by 2.5 to solve for p: p=2.520=8 Therefore, the value of p is 8.