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A cylindrical glass of water is 2.5 centimeters tall and holds a volume of 20 cubic centimeters of water.
The radius of the glass is 
sqrt((p)/( pi)) centimeters, where 
p is a constant. What is the value of 
p ?

A cylindrical glass of water is 22.55 centimeters tall and holds a volume of 2020 cubic centimeters of water.\newlineThe radius of the glass is pπ \sqrt{\frac{p}{\pi}} centimeters, where p p is a constant. What is the value of p p ?

Full solution

Q. A cylindrical glass of water is 22.55 centimeters tall and holds a volume of 2020 cubic centimeters of water.\newlineThe radius of the glass is pπ \sqrt{\frac{p}{\pi}} centimeters, where p p is a constant. What is the value of p p ?
  1. Given Information: The volume VV of a cylinder is given by the formula V=πr2hV = \pi r^2 h, where rr is the radius and hh is the height of the cylinder. We are given that the volume VV is 2020 cubic centimeters and the height hh is 2.52.5 centimeters. We are also given that the radius rr is pπ\sqrt{\frac{p}{\pi}} centimeters. We need to find the value of pp.
  2. Volume Formula Substitution: Substitute the given values into the volume formula: \newline20=π(pπ)2×2.520 = \pi(\sqrt{\frac{p}{\pi}})^2 \times 2.5 \newlineSimplify the equation by squaring the radius: \newline20=π(pπ)×2.520 = \pi(\frac{p}{\pi}) \times 2.5
  3. Divide and Solve: Cancel out the π\pi in the numerator and denominator: \newline20=p×2.520 = p \times 2.5 \newlineNow we have a simple equation to solve for pp.
  4. Calculate Value of pp: Divide both sides of the equation by 2.52.5 to solve for pp: \newlinep=202.5=8p = \frac{20}{2.5} = 8 \newline Therefore, the value of pp is 88.

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