8+10x^(2)÷(5y) when x=-2 and y=-4?

Substitute values into expression: Substitute the given values for x and y into the expression. We have x = -2 and y = -4, so we substitute these values into the expression 8 + 10x^(2) ÷ (5y).Calculate x squared: Calculate the value of x^(2). Since x = -2, we calculate (-2)^(2) = 4.Multiply by 10: Multiply the result from Step 2 by 10. We have 10 * 4 = 40.Calculate 5y: Calculate the value of 5y. Since y = -4, we calculate 5 * (-4) = -20.Divide results: Divide the result from Step 3 by the result from Step 4. We have 40 ÷ (-20) = -2.Add to 8: Add the result from Step 5 to 8. We have 8 + (-2) = 6.

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$8+10 x^{2} \div(5 y)$ when $x=-2$ and $y=-4 ?$

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Algebra 2

Composition of linear functions: find a value

Full solution

8+10 x^{2} \div(5 y)

when

x=-2

and

y=-4 ?

Substitute values into expression: Substitute the given values for $x$ and $y$ into the expression. $\newline$ We have $x = -2$ and $y = -4$ , so we substitute these values into the expression $8 + 10x^{2} \div (5y)$ .
Calculate $x$ squared: Calculate the value of $x^{2}$ . $\newline$ Since $x = -2$ , we calculate $(-2)^{2} = 4$ .
Multiply by $10$ : Multiply the result from Step $2$ by $10$ . We have $10 \times 4 = 40$ .
Calculate $5y$ : Calculate the value of $5y$ . $\newline$ Since $y = -4$ , we calculate $5 \times (-4) = -20$ .
Divide results: Divide the result from Step $3$ by the result from Step $4$ . $\newline$ We have $40 \div (-20) = -2$ .
Add to $8$ : Add the result from Step $5$ to $8$ . $\newline$ We have $8 + (-2) = 6$ .