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An object is launched from a platform.
Its height (in meters),
x seconds after the launch, is modeled by:

h(x)=-5x^(2)+20 x+60
What is the height of the object at the time of launch?
meters
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An object is launched from a platform. $\newline$ Its height (in meters), $x$ seconds after the launch, is modeled by: $\newline$ $h(x)=-5x^{2}+20x+60$ $\newline$ What is the height of the object at the time of launch? $\newline$ $\square$ meters

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Volume of cubes and rectangular prisms: word problems

Full solution

Q. An object is launched from a platform.

\newline

Its height (in meters),

x

seconds after the launch, is modeled by:

\newline

h(x)=-5x^{2}+20x+60

\newline

What is the height of the object at the time of launch?

\newline

\square

meters

Identify Launch Time: Identify the time of launch. The time of launch is when $x = 0$ seconds, since $x$ represents the time in seconds after the launch.
Substitute $x = 0$ : Substitute $x = 0$ into the height equation. $\newline$ The height equation is $h(x) = -5x^2 + 20x + 60$ . To find the height at the time of launch, we substitute $x$ with $0$ . $\newline$ $h(0) = -5(0)^2 + 20(0) + 60$
Calculate Launch Height: Calculate the height at the time of launch. $\newline$ $h(0) = -5(0) + 20(0) + 60$ $\newline$ $h(0) = 0 + 0 + 60$ $\newline$ $h(0) = 60$ $\newline$ The height of the object at the time of launch is $60$ meters.

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meters. Rocio observes that each time the ball bounces, it reaches a peak height which is

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1

\newline

h=4\cdot0.79^{(b-1)}

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