745 ×51

Question

745 ×51

Bytelearn · Accepted Answer

Set up problem: Set up the multiplication problem in the standard format. Write 745 above 51, with the larger number on top, and draw a line underneath them to prepare for multiplication.Multiply ones place: Multiply the digit in the ones place of the bottom number (1) by each digit of the top number (745). 1 × 5 = 5, write 5 below the line under the ones place. 1 × 4 = 4, write 4 next to the 5, under the tens place. 1 × 7 = 7, write 7 next to the 4, under the hundreds place. The partial product is 745.Multiply tens place: Multiply the digit in the tens place of the bottom number (5) by each digit of the top number (745), remembering to add a zero (place holder) for the tens place before writing the numbers. 5 × 5 = 25, write 5 and carry over 2. 5 × 4 = 20 plus the carried over 2 equals 22, write 2 and carry over another 2. 5 × 7 = 35 plus the carried over 2 equals 37, write 37. The partial product is 3725, but remember to add a zero at the end because we are multiplying by the tens place, making it 37250.Add partial products: Add the two partial products together to find the final product. Add 745 and 37250 together. 5 + 0 = 5 4 + 5 = 9 7 + 2 = 9 Since there are no more numbers to add in the thousands place, just bring down the 3 from 37250. The sum is 37995.

$745 \times 51$

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745×51745 \times 51745×51

$745 \times 51$