The, area of the rectangle below is 8(1)/(4) square inches. Find the perimeter. Show your work. Width is 4(1)/(2)in.

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The, area of the rectangle below is  8(1)/(4) square inches. Find the perimeter. Show your work.  Width is 4(1)/(2)in.

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Find Perimeter: To find the perimeter of a rectangle, we need to know both the length and the width. We already have the length, which is 4 1/2 inches. We can find the width by dividing the area by the length.Convert to Fractions: First, let's convert the mixed numbers to improper fractions to make the calculations easier. The area is 8 1/4 square inches, which is (8*4 + 1)/4 = 33/4 square inches. The length is 4 1/2 inches, which is (4*2 + 1)/2 = 9/2 inches.Calculate Width: Now, we divide the area by the length to find the width: (33/4) / (9/2) = (33/4) * (2/9) = 33/18 = 11/6 inches. This is the width of the rectangle.Perimeter Formula: The perimeter of a rectangle is given by the formula P = 2(l + w), where l is the length and w is the width. We have l = 9/2 inches and w = 11/6 inches.Add Fractions: Let's calculate the perimeter: P = 2[(9/2) + (11/6)]. First, we need a common denominator to add the fractions. The common denominator for 2 and 6 is 6.Find Common Denominator: Convert the length to a fraction with a denominator of 6: (9/2) * (3/3) = 27/6 inches. Now we can add the length and width: (27/6) + (11/6) = 38/6 inches.Multiply by 2: Multiply the sum by 2 to find the perimeter: P = 2 * (38/6) = 76/6 inches.Simplify Fraction: Simplify the fraction: 76/6 = 12 4/6 inches, and 4/6 can be simplified to 2/3, so the perimeter is 12 2/3 inches.

$7$ $-20$ . The, area of the rectangle below is $8 \frac{1}{4}$ square inches. Find the perimeter. Show your work. $\newline$ Width is $4 \frac{1}{2} \mathrm{in}$ .

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$7$ $-20$ . The, area of the rectangle below is $8 \frac{1}{4}$ square inches. Find the perimeter. Show your work. $\newline$ Width is $4 \frac{1}{2} \mathrm{in}$ .