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Let’s check out your problem:
6
x
+
7
y
=
4
x
+
4
y
6 x+7 y=4 x+4 y
6
x
+
7
y
=
4
x
+
4
y
\newline
Complete the missing value in the solution to the equation.
\newline
(
□
,
−
4
)
(\square,-4)
(
□
,
−
4
)
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Math Problems
Algebra 1
Does (x, y) satisfy the linear equation?
Full solution
Q.
6
x
+
7
y
=
4
x
+
4
y
6 x+7 y=4 x+4 y
6
x
+
7
y
=
4
x
+
4
y
\newline
Complete the missing value in the solution to the equation.
\newline
(
□
,
−
4
)
(\square,-4)
(
□
,
−
4
)
Isolate x terms:
Subtract
4
x
4x
4
x
from both sides of the equation to isolate terms with
x
x
x
on one side.
\newline
6
x
+
7
y
−
4
x
=
4
x
+
4
y
−
4
x
6x + 7y - 4x = 4x + 4y - 4x
6
x
+
7
y
−
4
x
=
4
x
+
4
y
−
4
x
\newline
This simplifies to:
\newline
2
x
+
7
y
=
4
y
2x + 7y = 4y
2
x
+
7
y
=
4
y
Isolate y terms:
Subtract
4
y
4y
4
y
from both sides of the equation to isolate terms with
y
y
y
on one side.
\newline
2
x
+
7
y
−
4
y
=
4
y
−
4
y
2x + 7y - 4y = 4y - 4y
2
x
+
7
y
−
4
y
=
4
y
−
4
y
\newline
This simplifies to:
\newline
2
x
+
3
y
=
0
2x + 3y = 0
2
x
+
3
y
=
0
Substitute
y
y
y
:
Substitute
y
=
−
4
y = -4
y
=
−
4
into the simplified equation.
2
x
+
3
(
−
4
)
=
0
2x + 3(-4) = 0
2
x
+
3
(
−
4
)
=
0
This simplifies to:
2
x
−
12
=
0
2x - 12 = 0
2
x
−
12
=
0
Solve for x:
Add
12
12
12
to both sides of the equation to solve for x.
\newline
2
x
−
12
+
12
=
0
+
12
2x - 12 + 12 = 0 + 12
2
x
−
12
+
12
=
0
+
12
\newline
This simplifies to:
\newline
2
x
=
12
2x = 12
2
x
=
12
Find x value:
Divide both sides of the equation by
2
2
2
to find the value of x.
\newline
2
x
2
=
12
2
\frac{2x}{2} = \frac{12}{2}
2
2
x
=
2
12
\newline
This simplifies to:
\newline
x
=
6
x = 6
x
=
6
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Line
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\newline
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9
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