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Solve the system of equations.
{[4x-y=11],[6x-2y=13]:}

Solve the system of equations.\newline{4xy=116x2y=13 \left\{\begin{array}{l}4 x-y=11 \\ 6 x-2 y=13\end{array}\right.

Full solution

Q. Solve the system of equations.\newline{4xy=116x2y=13 \left\{\begin{array}{l}4 x-y=11 \\ 6 x-2 y=13\end{array}\right.
  1. Write Equations: Write down the system of equations to be solved.\newlineWe have the following system of equations:\newline4xy=114x - y = 11 ...(11)\newline6x2y=136x - 2y = 13 ...(22)\newlineWe will solve this system using the method of substitution or elimination.
  2. Eliminate Variable: Look for a way to eliminate one of the variables.\newlineNotice that if we multiply equation (11) by 22, we get:\newline2×(4xy)=2×112\times(4x - y) = 2\times11\newline8x2y=228x - 2y = 22 ...(33)\newlineNow we have the coefficients of yy in equations (2)(2) and (3)(3) as equal but opposite in sign, which means we can add the equations to eliminate yy.
  3. Add Equations: Add equations (2)(2) and (3)(3) to eliminate yy.
    (6x2y)+(8x2y)=13+22(6x - 2y) + (8x - 2y) = 13 + 22
    6x+8x2y2y=356x + 8x - 2y - 2y = 35
    14x=3514x = 35
  4. Solve for x: Solve for x.\newlineDivide both sides of the equation by 1414 to find the value of x.\newline14x14=3514\frac{14x}{14} = \frac{35}{14}\newlinex=3514x = \frac{35}{14}\newlinex=2.5x = 2.5
  5. Substitute xx: Substitute the value of xx back into one of the original equations to find yy. We can use equation (11) for this purpose. 4xy=114x - y = 11 4(2.5)y=114*(2.5) - y = 11 10y=1110 - y = 11
  6. Solve for y: Solve for y.\newlineSubtract 1010 from both sides of the equation to isolate yy.\newliney=1110-y = 11 - 10\newliney=1-y = 1\newlineMultiply both sides by 1-1 to get the value of yy.\newliney=1y = -1