6.1.2 Exam: Semester Exam (Computer-Scored) Question 6 of 30 Solve the equation below for x using any method: x^(2)=8x-35 A. x=-7;x=5 B. 3+-5i c. 4+-sqrt19 D. 4+-isqrt19 PREVIOUS

Set Equation to Zero: Step 1: Start by setting the equation to zero to use the quadratic formula. x^2 - 8x + 35 = 0 Identify Coefficients: Step 2: Identify coefficients for the quadratic formula, where a = 1, b = -8, and c = 35. a = 1, b = -8, c = 35 Plug into Quadratic Formula: Step 3: Plug the coefficients into the quadratic formula x = (-b ± sqrt(b^2 - 4ac)) / 2a. x = (8 ± sqrt((-8)^2 - 4*1*35)) / 2*1 Calculate Discriminant: Step 4: Calculate the discriminant (b^2 - 4ac). Discriminant = 64 - 140 = -76

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6.1.2 Exam: Semester Exam (Computer-Scored)
Question 6 of 30
Solve the equation below for
x using any method:

x^(2)=8x-35
A.
x=-7;x=5
B.
3+-5i
c.
4+-sqrt19
D.
4+-isqrt19
PREVIOUS

Solve the equation below for $x$ using any method: $\newline$ $x^{2}=8x-35$ $\newline$ A). $x=-7;x=5$ $\newline$ B). $3\pm5i$ $\newline$ C). $4\pm\sqrt{19}$ $\newline$ D). $4\pm i\sqrt{19}$

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Math Problems

Algebra 2

Composition of linear and quadratic functions: find an equation

Full solution

Q. Solve the equation below for

x

using any method:

\newline

x^{2}=8x-35

\newline

A).

x=-7;x=5

\newline

B).

3\pm5i

\newline

C).

4\pm\sqrt{19}

\newline

D).

4\pm i\sqrt{19}

Set Equation to Zero: Step $1$ : Start by setting the equation to zero to use the quadratic formula. $\newline$ $x^2 - 8x + 35 = 0$
Identify Coefficients: Step $2$ : Identify coefficients for the quadratic formula, where $a = 1$ , $b = -8$ , and $c = 35$ . $\newline$ $a = 1$ , $b = -8$ , $c = 35$
Plug into Quadratic Formula: Step $3$ : Plug the coefficients into the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ . $\newline$ $x = \frac{8 \pm \sqrt{(-8)^2 - 4\cdot 1\cdot 35}}{2\cdot 1}$
Calculate Discriminant: Step $4$ : Calculate the discriminant $b^2 - 4ac$ . $\newline$ Discriminant = $64 - 140 = -76$