Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

The eleventh term of the sequence \newline3,6,12,24,3,-6,12,-24,\dots, is\newline(1)3072(1) -3072\newline(2)3072(2) 3072\newline(3)6144(3) -6144\newline(4)6144(4) 6144

Full solution

Q. The eleventh term of the sequence \newline3,6,12,24,3,-6,12,-24,\dots, is\newline(1)3072(1) -3072\newline(2)3072(2) 3072\newline(3)6144(3) -6144\newline(4)6144(4) 6144
  1. Identify Pattern: Identify the pattern in the sequence.\newlineThe sequence alternates signs and each term is multiplied by 2-2 from the previous term.\newlineCalculation: 6=3×2-6 = 3 \times -2, 12=6×212 = -6 \times -2, 24=12×2-24 = 12 \times -2.
  2. General Formula: Determine the general formula for the nth term.\newlineSince each term is multiplied by 2-2, the nth term can be expressed as an=3×(2)n1 a_n = 3 \times (-2)^{n-1} .\newlineCalculation: a2=3×(2)21=6 a_2 = 3 \times (-2)^{2-1} = -6 , which matches the sequence.
  3. Calculate Eleventh Term: Calculate the eleventh term using the formula.\newlineUsing an=3×(2)n1 a_n = 3 \times (-2)^{n-1} , find a11=3×(2)111 a_{11} = 3 \times (-2)^{11-1} .\newlineCalculation: a11=3×(2)10=3×1024=3072 a_{11} = 3 \times (-2)^{10} = 3 \times 1024 = 3072 .

More problems from Powers of i