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Solve for jj: 4(3j+(4))94(3j+(-4))-9

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Q. Solve for jj: 4(3j+(4))94(3j+(-4))-9
  1. Distribute 44: Distribute 44 into the parentheses.\newlineCalculation: 4(3j+(4))=4×3j+4×(4)=12j164(3j + (-4)) = 4\times3j + 4\times(-4) = 12j - 16
  2. Subtract 99: Subtract 99 from the result of the distribution.\newlineCalculation: (12j16)9=12j25(12j - 16) - 9 = 12j - 25

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