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Let’s check out your problem:
Solve the equation
4
×
3
33
=
4
x
2
4\times3^{33}=4x^2
4
×
3
33
=
4
x
2
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Math Problems
Algebra 2
Convert between exponential and logarithmic form: rational bases
Full solution
Q.
Solve the equation
4
×
3
33
=
4
x
2
4\times3^{33}=4x^2
4
×
3
33
=
4
x
2
Identify base and exponent:
Identify the base and the exponent in the given equation.
4
×
3
33
=
4
x
2
4\times3^{33}=4x^2
4
×
3
33
=
4
x
2
can be simplified by dividing both sides by
4
4
4
.
Divide by
4
4
4
:
Divide both sides by
4
4
4
to simplify the equation.
\newline
3
33
=
x
2
3^{33} = x^2
3
33
=
x
2
Take square root:
Take the
square root
of both sides to solve for
x
x
x
.
3
33
=
x
2
\sqrt{3^{33}}=\sqrt{x^2}
3
33
=
x
2
Simplify square root:
Simplify the square root of
x
2
x^2
x
2
and the exponent.
\newline
x
=
3
33
2
x=3^{\frac{33}{2}}
x
=
3
2
33
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Question
Which property of logarithms does this equation demonstrate?
\newline
log
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\newline
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\newline
(A)
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\newline
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\newline
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\newline
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6
6
6
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6
6
6
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\newline
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