4(1-t)=5t^(2) Let t=x and t=y be the solutions to the given equation. What is the value of -xy ?

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4(1-t)=5t^(2) Let  t=x and  t=y be the solutions to the given equation. What is the value of  -xy ?

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Write and expand equation: Write down the given equation and expand it. The given equation is 4(1-t) = 5t^2. Expanding the left side gives us 4 - 4t = 5t^2.Rearrange to form quadratic equation: Rearrange the equation to form a quadratic equation. Bring all terms to one side to set the equation to zero. 0 = 5t^2 + 4t - 4Use quadratic formula: Use the quadratic formula to find the solutions for t. The quadratic formula is t = (-b ± √(b^2 - 4ac)) / (2a), where a = 5, b = 4, and c = -4.Calculate discriminant: Calculate the discriminant (b^2 - 4ac). Discriminant = (4)^2 - 4(5)(-4) = 16 + 80 = 96.Calculate solutions: Calculate the solutions using the quadratic formula. t = (-4 ± √96) / (10) Since we are looking for the product of the solutions, we don't need to calculate them separately.Apply Vieta's formulas: Apply Vieta's formulas, which state that for a quadratic equation ax^2 + bx + c = 0, the sum of the roots is -b/a and the product of the roots is c/a. For the equation 5t^2 + 4t - 4 = 0, the product of the roots, xy, is c/a = -4/5.Calculate -xy: Calculate the value of -xy. -xy = -(-4/5) = 4/5

$4(1-t)=5 t^{2}$ $\newline$ Let $t=x$ and $t=y$ be the solutions to the given equation. What is the value of $-x y$ ?

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4(1−t)=5t2 4(1-t)=5 t^{2} 4(1−t)=5t2\newlineLet t=x t=x t=x and t=y t=y t=y be the solutions to the given equation. What is the value of −xy -x y −xy ?

$4(1-t)=5 t^{2}$ $\newline$ Let $t=x$ and $t=y$ be the solutions to the given equation. What is the value of $-x y$ ?