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Let’s check out your problem:
3
y
+
11
y
=
28
3 y+11 y=28
3
y
+
11
y
=
28
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Math Problems
Grade 8
Describe the graph of a linear equation
Full solution
Q.
3
y
+
11
y
=
28
3 y+11 y=28
3
y
+
11
y
=
28
Combine Like Terms:
Combine like terms by adding the coefficients of
y
y
y
together.
\newline
3
y
+
11
y
=
(
3
+
11
)
y
=
14
y
3y + 11y = (3+11)y = 14y
3
y
+
11
y
=
(
3
+
11
)
y
=
14
y
Solve for y:
Solve for y by dividing both sides of the equation by the coefficient of
y
y
y
, which is
14
14
14
.
\newline
y
=
28
14
y = \frac{28}{14}
y
=
14
28
\newline
y
=
2
y = 2
y
=
2
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