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Let’s check out your problem:
3
x
(
10
+
x
2
)
=
15
x
3x\left(\frac{10+x}{2}\right)=15x
3
x
(
2
10
+
x
)
=
15
x
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Math Problems
Algebra 1
Add and subtract polynomials
Full solution
Q.
3
x
(
10
+
x
2
)
=
15
x
3x\left(\frac{10+x}{2}\right)=15x
3
x
(
2
10
+
x
)
=
15
x
Distribute
3
x
3x
3
x
:
Distribute the
3
x
3x
3
x
across the terms inside the parentheses.
\newline
3
x
×
(
10
2
)
+
3
x
×
(
x
2
)
=
15
x
3x \times (\frac{10}{2}) + 3x \times (\frac{x}{2}) = 15x
3
x
×
(
2
10
)
+
3
x
×
(
2
x
)
=
15
x
Simplify multiplication:
Simplify the multiplication inside the parentheses.
3
x
×
5
+
3
x
×
(
1
2
)
x
=
15
x
3x \times 5 + 3x \times (\frac{1}{2})x = 15x
3
x
×
5
+
3
x
×
(
2
1
)
x
=
15
x
Continue simplifying:
Continue simplifying the equation.
15
x
+
(
3
2
)
x
2
=
15
x
15x + \left(\frac{3}{2}\right)x^2 = 15x
15
x
+
(
2
3
)
x
2
=
15
x
Subtract
15
x
15x
15
x
:
Subtract
15
x
15x
15
x
from both sides to move all terms involving
x
x
x
to one side.
\newline
15
x
+
(
3
2
)
x
2
−
15
x
=
15
x
−
15
x
15x + \left(\frac{3}{2}\right)x^2 - 15x = 15x - 15x
15
x
+
(
2
3
)
x
2
−
15
x
=
15
x
−
15
x
Simplify equation:
Simplify both sides of the equation.
\newline
(
3
2
)
x
2
=
0
(\frac{3}{2})x^2 = 0
(
2
3
)
x
2
=
0
Conclude
x
=
0
x=0
x
=
0
:
Since
3
2
x
2
=
0
\frac{3}{2}x^2 = 0
2
3
x
2
=
0
, we can conclude that
x
x
x
must be
0
0
0
for the equation to hold true.
\newline
x
=
0
x = 0
x
=
0
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(
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=
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−
9
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\newline
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\newline
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\text{[[even][odd][neither]]}
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)
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r
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)
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\newline
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x
+
7
)
(
x
+
4
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(
x
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7
)
(
x
+
4
)
\newline
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\newline
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