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$33$ In which example is the current $1.0\,\text{A}$ ? $\newline$ A a $10\,\text{V}$ lamp with input power $0.10\,\text{W}$ $\newline$ P= $I^{2}$ , E= $I$ $\newline$ B a resistor of resistance $0.50\,\Omega$ with a potential difference (P.d.) of $2.0\,\text{V}$ across it $\newline$ C two resistors with a current of $0.50\,\text{A}$ connected in series

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Compare linear and exponential growth

Full solution

Q.

33

In which example is the current

1.0\,\text{A}

?

\newline

A a

10\,\text{V}

lamp with input power

0.10\,\text{W}

\newline

P=

I^{2}

, E=

I

\newline

B a resistor of resistance

0.50\,\Omega

with a potential difference (P.d.) of

2.0\,\text{V}

across it

\newline

C two resistors with a current of

0.50\,\text{A}

connected in series

Identify Formula: Identify the formula to use for each option and calculate the current. $\newline$ Option A: $10\,\text{V}$ lamp with input power $0.10\,\text{ix}$ . Using $P = I^2$ , solve for $I$ . $\newline$ $I = \sqrt{P} = \sqrt{0.10} = 0.316\,\text{A}.$
Calculate Option A: Option B is not clearly defined in the problem statement, so skip to Option C. $\newline$ Option C: A resistor of resistance $0.50 \, \Omega$ with a potential difference of $2.0\,V$ across it. Using Ohm's Law, $I = \frac{V}{R}$ . $\newline$ $I = \frac{2.0\,V}{0.50\,\Omega} = 4.0\,A$ .
Skip to Option C: Option D: Two resistors with a current of $0.50\,\text{A}$ connected in series. The total current in a series circuit is the same through each component. $\newline$ $I = 0.50\,\text{A}.$

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