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3(x+2)−2(2x−3)3 (x + 2) - 2 (2x - 3)

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Full solution

Q. 3(x+2)−2(2x−3)3 (x + 2) - 2 (2x - 3)
  1. Distribute 33 to terms: Distribute 33 to each term inside the parentheses x+2x + 2.3(x+2)=3×x+3×2=3x+63(x + 2) = 3\times x + 3\times 2 = 3x + 6
  2. Distribute −2-2 to terms: Distribute −2-2 to each term inside the parentheses (2x−3)(2x - 3).\newline\(-2(22x - 33) = −2-2\cdot22x + −2-2\cdot(−3-3)(\newline\)= −4-4x + 66
  3. Combine distributed results: Combine the results from Step 11 and Step 22. 3x+6−4x+63x + 6 - 4x + 6
  4. Combine like terms: Combine like terms.\newline3x−4x+6+63x - 4x + 6 + 6\newline= −1x+12-1x + 12\newline= −x+12-x + 12

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