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3(2n2)1=943(2n-2)-1=\frac{9}{4}

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Q. 3(2n2)1=943(2n-2)-1=\frac{9}{4}
  1. Distribute and Simplify: Distribute the 33 into the parentheses.3(2n2)1=3×2n3×213(2n-2)-1 = 3\times 2n - 3\times 2 - 1=6n61= 6n - 6 - 1=6n7= 6n - 7
  2. Addition to Isolate Variable: Add 77 to both sides to isolate the term with the variable nn on one side.\newline6n7+7=94+76n - 7 + 7 = \frac{9}{4} + 7\newline6n=94+2846n = \frac{9}{4} + \frac{28}{4}\newline6n=3746n = \frac{37}{4}
  3. Divide to Solve for n: Divide both sides by 66 to solve for n.\newline6n/6=(37/4)/66n / 6 = (37/4) / 6\newlinen=(37/4)(1/6)n = (37/4) \cdot (1/6)\newlinen=37/24n = 37/24

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