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Let’s check out your problem:
3
(
2
n
−
2
)
−
1
=
9
4
3(2n-2)-1=\frac{9}{4}
3
(
2
n
−
2
)
−
1
=
4
9
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Math Problems
Algebra 2
Add, subtract, multiply, and divide polynomials
Full solution
Q.
3
(
2
n
−
2
)
−
1
=
9
4
3(2n-2)-1=\frac{9}{4}
3
(
2
n
−
2
)
−
1
=
4
9
Distribute and Simplify:
Distribute the
3
3
3
into the parentheses.
3
(
2
n
−
2
)
−
1
=
3
×
2
n
−
3
×
2
−
1
3(2n-2)-1 = 3\times 2n - 3\times 2 - 1
3
(
2
n
−
2
)
−
1
=
3
×
2
n
−
3
×
2
−
1
=
6
n
−
6
−
1
= 6n - 6 - 1
=
6
n
−
6
−
1
=
6
n
−
7
= 6n - 7
=
6
n
−
7
Addition to Isolate Variable:
Add
7
7
7
to both sides to isolate the term with the variable
n
n
n
on one side.
\newline
6
n
−
7
+
7
=
9
4
+
7
6n - 7 + 7 = \frac{9}{4} + 7
6
n
−
7
+
7
=
4
9
+
7
\newline
6
n
=
9
4
+
28
4
6n = \frac{9}{4} + \frac{28}{4}
6
n
=
4
9
+
4
28
\newline
6
n
=
37
4
6n = \frac{37}{4}
6
n
=
4
37
Divide to Solve for n:
Divide both sides by
6
6
6
to solve for n.
\newline
6
n
/
6
=
(
37
/
4
)
/
6
6n / 6 = (37/4) / 6
6
n
/6
=
(
37/4
)
/6
\newline
n
=
(
37
/
4
)
⋅
(
1
/
6
)
n = (37/4) \cdot (1/6)
n
=
(
37/4
)
⋅
(
1/6
)
\newline
n
=
37
/
24
n = 37/24
n
=
37/24
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