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3=(1)/(2x)+(2x-3)/(2x)

3=12x+2x32x 3=\frac{1}{2 x}+\frac{2 x-3}{2 x}

Full solution

Q. 3=12x+2x32x 3=\frac{1}{2 x}+\frac{2 x-3}{2 x}
  1. Combine fractions: Combine the fractions on the right side of the equation.\newlineSince both fractions have the same denominator, we can combine them into a single fraction.\newline(12x)+(2x32x)=(1+2x32x)(\frac{1}{2x}) + (\frac{2x-3}{2x}) = (\frac{1 + 2x - 3}{2x})
  2. Simplify numerator: Simplify the numerator of the combined fraction. \newline1+2x3=2x21 + 2x - 3 = 2x - 2\newlineNow the equation is 3=2x22x3 = \frac{2x - 2}{2x}
  3. Multiply by 2x2x: Multiply both sides of the equation by 2x2x to eliminate the fraction.\newline3×2x=(2x2)3 \times 2x = (2x - 2)\newline6x=2x26x = 2x - 2
  4. Subtract 2x2x: Subtract 2x2x from both sides of the equation to isolate the variable on one side.\newline6x2x=2x22x6x - 2x = 2x - 2 - 2x\newline4x=24x = -2
  5. Divide by 44: Divide both sides of the equation by 44 to solve for x.\newline4x/4=2/44x / 4 = -2 / 4\newlinex=1/2x = -1/2

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