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2x+3y=5x-y
Complete the missing value in the solution to the equation.

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2x+3y=5xy 2 x+3 y=5 x-y \newlineComplete the missing value in the solution to the equation.\newline(,0) (\square, 0)

Full solution

Q. 2x+3y=5xy 2 x+3 y=5 x-y \newlineComplete the missing value in the solution to the equation.\newline(,0) (\square, 0)
  1. Find x-coordinate: First, we need to find the x-coordinate of the point where the line intersects the x-axis. At this point, the y-coordinate is 00. So we substitute y=0y = 0 into the equation 2x+3y=5xy2x + 3y = 5x - y.
  2. Substitute y=0y=0: Substituting y=0y = 0 into the equation gives us 2x+3(0)=5x(0)2x + 3(0) = 5x - (0), which simplifies to 2x=5x2x = 5x.
  3. Solve for x: To solve for x, we need to get all the x terms on one side of the equation. We can do this by subtracting 2x2x from both sides, which gives us 0=5x2x0 = 5x - 2x.
  4. Divide by 33: Simplifying the right side of the equation, we get 0=3x0 = 3x.
  5. Final x value: To find the value of x, we divide both sides by 33, which gives us x=03x = \frac{0}{3}.
  6. Final x value: To find the value of x, we divide both sides by 33, which gives us x=03x = \frac{0}{3}. Simplifying the fraction 03\frac{0}{3} gives us x=0x = 0.

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