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2root(3)(x)+5=1

2x3+5=1 2 \sqrt[3]{x}+5=1

Full solution

Q. 2x3+5=1 2 \sqrt[3]{x}+5=1
  1. Isolate x term: Isolate the term with the variable xx.\newlineTo isolate the term with xx, we need to subtract 55 from both sides of the equation.\newline23(x)+55=152\sqrt{3}(x) + 5 - 5 = 1 - 5\newline23(x)=42\sqrt{3}(x) = -4
  2. Divide by 232\sqrt{3}: Divide both sides by 232\sqrt{3} to solve for xx.x=4(23)x = \frac{-4}{(2\sqrt{3})}
  3. Rationalize denominator: Simplify the fraction by multiplying the numerator and denominator by 3\sqrt{3} to rationalize the denominator.x=4323×3x = \frac{-4\sqrt{3}}{2\sqrt{3} \times \sqrt{3}}x=436x = \frac{-4\sqrt{3}}{6}
  4. Simplify fraction: Simplify the fraction further by dividing both the numerator and the denominator by 22.x=233x = \frac{-2\sqrt{3}}{3}

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