There are 12 counters in a bag.3 of the counters are red9 of the counters are greenAmeya, Jack and Ella each take at random one counter from the bag.Work out the probability that at least one red counter is still in the bag.
Q. There are 12 counters in a bag.3 of the counters are red9 of the counters are greenAmeya, Jack and Ella each take at random one counter from the bag.Work out the probability that at least one red counter is still in the bag.
Question Prompt: question_prompt: What's the probability that at least one red counter is left in the bag after Ameya, Jack, and Ella each take one?
Total Counters: Total counters in the bag: 12. Red counters: 3. Green counters: 9.
Probability for Ameya: Probability that the first person (Ameya) does not take a red counter: 9 green counters / 12 total counters = 43.
Probability for Jack: After Ameya's turn, if no red counter is taken, there are 11 counters left with 3 red and 8 green. Probability that the second person (Jack) does not take a red counter: 8 green counters / 11 total counters.
Probability for Ella: Probability calculation for Jack: 118.
Calculation for At Least One Red Counter: If Jack also doesn't take a red counter, there are now 10 counters left with 3 red and 7 green. Probability that the third person (Ella) does not take a red counter: 10 total counters7 green counters.
Combined Probability Calculation: Probability calculation for Ella: 107.
Calculation Error: To find the probability that at least one red counter is left, we calculate the probability that no red counters are taken and subtract it from 1.
Calculation Error: To find the probability that at least one red counter is left, we calculate the probability that no red counters are taken and subtract it from 1. Combined probability that no red counters are taken by any of the three people: (43)×(118)×(107).
Calculation Error: To find the probability that at least one red counter is left, we calculate the probability that no red counters are taken and subtract it from 1. Combined probability that no red counters are taken by any of the three people: (43)×(118)×(107). Calculation error: The combined probability should be (129)×(118)×(107), not (43)×(118)×(107).